$uppersum,U=\sum_1^nM_i×(x_i-x_{i-1})$ u p p e r s u m , U =∑ 1 n M i ×( x i − x i −1). $lowersum,L=\sum_1^nn_i×(x_i-x_{i-1})$ l o w e r s u m , L =∑ 1 ...
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