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Let y=sec-1x, then secy=x, y∈[0,π/2)∪(π/2,π]. (sec-1x)'=1 ...

L28 The inverse Triogonometric functions (Conti.) (續.反三角函數). Ch.8 Techniques of integrations. 8.1 Review (配方法). 8.2 Integration by parts (分部積分).

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