... −sinx (tanx) ′ =sec 2 x , (cotx) ′ =−csc2x (secx) ′ = secx tanx ,(cscx) ... 2 微分形式: d(C)=0 , d(xa)=axa−1xd d(ax) = a x lnxad , d(ex) = e x dx 2 x ...
確定！ 回上一頁
