不過還是google了一下,發現一個有趣的公式:0^0 = 0^(1 - 1) = 0^1×0^-1 = (0/1)^1×(0/1)^-1 = (0/1)^1×(1/0)^1 = 0/0 = nullity. 10 芳芳. 0的0次方 ...
確定! 回上一頁