... we get sin 30 cos30 1 2 sin 30 2 = 0 pb с 1 cos 30 + sin 30 2 A a - p q- b 0 a - p 0 r - C a pq- b рь sin30 cos30 [ ( 4sin 30 – 2 cos 30 – 2sin 30 ) ...
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