sin 4x 2f ' ( x ) f ' ( x ) = t Put ⇒2t2 - 2 ( cos 2x - sin 2x ) t − sin 4x = 1 ← 11 f ' ( x )4t = 2 ( cos 2x - sin 2x ) ± ⇒ 2t = ( cos 2x - sin 2x ) ...
確定！ 回上一頁
