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How to prove that {1/2^n} is bounded series ? | Socratic

{12n} is bounded since 0<12n≤12 . Explanation: For all natural number n ,. (a) 0<2n⇒0<12n. (b) n≥1⇒2n≥21⇒12n≤121. So, 0<12n≤12 for ...

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