雖然這篇canOpenURL鄉民發文沒有被收入到精華區:在canOpenURL這個話題中,我們另外找到其它相關的精選爆讚文章
[爆卦]canOpenURL是什麼?優點缺點精華區懶人包
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#1canOpenURL(_:) | Apple Developer Documentation
canOpenURL (_:). Returns a Boolean value that indicates whether an app is available to handle a URL scheme. Language. SwiftObjective-C. Availability.
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#2關於canOpenURL 的一些事. 前言 - Phineas
canOpenURL. iOS 9 上面出於對於用戶隱私保護,開發者不能像以前依樣無限制使用canOpenURL api 來判斷使用者有安裝哪些app,其實想想這也是對的,如果能拿到用戶的app ...
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#3iOS9 以后openURL 和canOpenURL 使用限制的小误区
iOS9 限制了 openURL: 和 canOpenURL: 方法的使用,如果我们要调起第三方App,需要在 Info.plist 的 LSApplicationQueriesSchemes Key 中添加相应App ...
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#4Difference between openURL & canOpenURL - Stack Overflow
canOpenURL : It returns the bool, whther the url can be opened or not. Example: func schemeAvailable(scheme: String) -> Bool { if ...
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#5[iOS] canOpenUrl 無法開啟 - Mr.Lin - 痞客邦
升級到iOS 9 隱私權方面更加嚴謹了所以原來使用OpenUrl 或是canOpenUrl 的方式都會不能使用必須要加上白名單處理再info.plist 增加LSApplic.
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#6关于-canOpenURL: 和-openURL: 的那些事- 我的学习历程
最近工作中需要知道用户的iPhone 上都安装了哪些应用,所以查阅了一些资料。总的来说主要还是通过使用Apple 提供的 - canOpenURL: API 来测试相应APP 的 ...
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#7iOS 應用之間的跳轉(OC&Swift)
NSURL *url = [NSURL URLWithString:@"itms-apps://itunes.apple.com/app/id1129144823"]; // 注意: 跳轉之前, 可以使用canOpenURL: 判斷是否可以跳轉 ...
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#8Querying URL Schemes with canOpenURL - Use Your Loaf
Typically you first query for the URL scheme of the application with canOpenURL: then you open it with openURL: . A typical Objective-C code ...
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#9UIApplication.CanOpenUrl(NSUrl) Method (UIKit) - Microsoft ...
CanOpenUrl (NSUrl) Method. Definition. Namespace: UIKit. Assembly: Xamarin.iOS.dll. Important. Some information relates to prerelease product that may be ...
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#10API Reference | Libraries | system | canOpenURL - Solar2D ...
canOpenURL (). Type, Function. Library, system.*. Return value, Boolean. Revision, Release 2021.3646. Keywords, system, canOpenURL, URL. See also, system.
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#11Linking - React Native
canOpenURL (url); if (supported) { // Opening the link with some app, if the URL scheme is "http" the web link should be opened // by some ...
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#12ios - openURL 和canOpenURL 的区别 - IT工具网
openURL/open 或 canOpenURL 。 谁能帮我解释一下这两个功能之间的实际区别? if #available(iOS 10.0, *) { UIApplication.shared.open(URL(string: urlStr)!, ...
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#13canopenurl - 菜鳥學院 - 菜鸟学院
2019-12-20 warning 還沒有 配置 qq 好友 分享 url scheme qq41e804da qq 41 e 804 da 沒法 進行 分享 canopenurl failed url mqzoneopensdkapiv2 mqzoneopensdkapiv 2 ...
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#14`Linking.canOpenURL(url)` returns `false` in a context where ...
Description Linking.canOpenURL(url) returns false despite the fact that Linking.openURL(url) works. Only on certain android devices, ...
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#15App Launcher Capacitor Plugin API
canOpenUrl ({ url: 'com.getcapacitor.myapp' }); alert('Can open url: ', value); }; const openPortfolioPage = async () => { await AppLauncher.
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#16[iOS9] canOpenURL return false - 小賢的部落格- 痞客邦
想在App裡開啟其它App,在iOS 9需加入"LSApplicationQueriesSchemes" 白名單。 參考資料: http://stackoverf.
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#17嘗試呼叫canOpenURL的iOS 9上的Google登入崩潰 - 程式人生
signInSilently() 最終會在內部Google Sign-In SDK呼叫 canOpenURL 時崩潰。 ... to query for scheme com-google-gidconsent-google" -canOpenURL: failed for URL: ...
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#18[SWIFT] [IOS] canOpenURL becomes false on iOS14
Verification environment. Xcode: 12.0.1 iOS: 14.0 Swift: 5. Event. When I tried to start the browser externally with the code below, the canOpenURL method ...
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#19关于ios:为什么canOpenURL这么多? | 码农家园
Why so many canOpenURL?从https://doc.open.alipay.com/doc2/detail?treeId=54运行AlipaySDK演示时[collapse title=]看到它一旦帮助 ...
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#20apple.uikit.UIApplication.canOpenURL java code examples
canOpenURL (Showing top 3 results out of 315). Add the Codota plugin to your IDE and get smart completions. private void myMethod () {.
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#21Uiapplication shared canopenurl swiftui
For mobile applications canOpenURL function is available). code structure. ... 参考: canOpenURL(_:) - UIApplication | Apple Developer Documentation.
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#22iOS9 以後openURL 和canOpenURL 使用限制的小誤區 - ITW01
iOS9 限制了 openURL: 和 canOpenURL: 方法的使用,如果我們要調起第三方App,需要在 Info.plist 的 LSApplicationQueriesSchemes Key 中新增相應App ...
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#23iOS14 适配canOpenURL问题 - 简书
问题部分升级到iOS 14的用户,在点击链接跳转的时候,[[UIApplication sharedApplication]canOpenURL:url]返回false经定...
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#24iOS14 适配canOpenURL问题- 云+社区 - 腾讯云
部分升级到iOS 14的用户,在点击链接跳转的时候,[[UIApplication sharedApplication]canOpenURL:url]返回false 经定位,是因为iOS 14新增默认浏览器 ...
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#25canOpenURL returning true for custom URL scheme even if ...
NSString *customURL = @"mycustomurl://"; if ([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:customURL]]) { [[UIApplication ...
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#26iOS9: canOpenURL returning false for WhatApp's url scheme
iOS9: canOpenURL returning false for WhatApp's url scheme. In iOS 9 you must whitelist any URL schemes your App wants to query in Info.plist under the ...
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#27canOpenURL always returns false - Oleksandr Yolkin
On iOS 14 the construction canOpenURL does not work i.e. canOpenURL always returns false if the default browser was changed.
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#28如何自其它應用程式連結WhatsApp
如您要使用-[UIApplication canOpenURL:] 來確定WhatsApp 是否安裝在使用者的iPhone ,請確認在您應用程式Info.plist 檔案中的LSApplicationQueriesSchemes 機碼內 ...
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//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#29iOS canOpenURL 返回true,但未安装应用程序(facebook)
canOpenURL (URL(string: "fb://")!)enter code here 在URL Schemes 中,我添加了fb,所以也不要错过那部分。 但是canOpenURL 返回 TRUE !但该应用程序已卸载。
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#30iOS开发 - CSDN博客
-canOpenURL: failed for URL: "weixinULAPI://" - error: "This app is not allowed to query for scheme weixinulapi".
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#31測試canOpenURL on iPhone - YouTube
測試canOpenURL on iPhone. 67 views67 views. Oct 31, 2018. 0. 0. Share. Save. 0 / 0. comingcom. comingcom ...
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#32使用WhatsApp呼叫反應Native Linking.canOpenURL() - IT閱讀
canOpenURL (). 阿新• • 發佈:2020-12-07. 我正在嘗試建立一個連結以從我的本機應用程式開始在whatsapp上進行對話,但是方法Linking.canOpenURL()始終將false調整為.
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#33Question Silence "-canOpenURL: failed for URL:" - TitanWolf
I have added my URL schemes to Info.plist, as required by iOS 9. However, calls result in: -canOpenURL: failed for URL: "scheme://" - error: "(null)".
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#34iOS9: canOpenURL returning false for WhatApp's url scheme
Note that this mechanism only applies to canOpenURL and not openURL. You do not need to have a scheme listed in Info.plist to be able to open it with ...
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#35Dovov编程网
我已经看到Facebooklogin问题– canOpenURL:URL失败:“fbauth2:///” – 错误:“(null)”,但我有FBSDKCoreKit框架。 我也见过Facebook SDK 4.5 IOS 9,但它的答案并不能 ...
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#36Linking.canOpenUrl does not work - Expo SDK - Forums
canOpenUrl does not work properly with Expo it seems. My use case is opening the Instagram app on a specific media ID if installed, ...
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#37iOS14 適配canOpenURL問題 - 小科科的春天
問題. 部分升級到iOS 14的用戶,在點擊鏈接跳轉的時候,[[UIApplication sharedApplication]canOpenURL:url]返回false 經定位,是因為iOS 14新增默認 ...
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#38Handling URL Schemes - iOS Tutorial - SO Documentation
canOpenURL method verifies if there is any app which can handle indicated URL scheme. // Swift. UIApplication.sharedApplication().canOpenURL(_ aUrl: NSURL).
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#39適配ios9出現的問題:-canOpenURL: failed for URL - JavaShuo
個人解決方法是:api info.plist中找到LSApplicationQueriesSchemes, 而後在下方添加Keyiphone 如:-canOpenURL: failed for URL:
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#40App.CanOpenUrl() ?? | B4X Programming Forum
iOS Question App.CanOpenUrl() ?? ... String = "https://www.youtube.com/watch?v=TR0svC5KVeE" If App.CanOpenURL(link) Then App.OpenURL(link).
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#4125. iOS9 以后openURL 和canOpenURL 使用限制的小误区
iOS9 限制了openURL: 和canOpenURL: 方法的使用,如果我们要调起第三方App,需要在Info.plist 的LSApplicationQueriesSchemes Key 中添加相应App 的Scheme 才行,且 ...
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#42iOS10適配:被棄用的openURL | 程式前沿
不過在iOS 9中,相關的canOpenURL:函式已經被私有化了,蘋果禁止開發者查詢裝置上是否安裝了某款APP。在iOS 10中,蘋果棄用了openURL, ...
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#43Dropbox API Support & Feedback
Re: -canOpenURL: failed for URL: "dbapi-8-emm://1/connect" - error: "The operation co. Labels: APIs. Re: -canOpenURL: failed for URL: ...
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#44App rejected because it uses canOpenURL in an ...
I guess that this native call (canOpenURL) gets called either when calling the AS3 method navigateToURL, or by using one of the several ANEs ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#45URL Scheme / 系統是否安裝某App / 應用間跳轉整理 - 台部落
https://www.jianshu.com/p/c73d3eb2d081 我對“是否安裝某App”問題的第一反應是,調用系統UIApplication對象的實例方法canOpenURL:來判斷, ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#46swift ios9 - 秀儿今日热榜
swift - Swift canOpenURL()错误iOS9隐私问题tel://和telprompt:// swift ios9. @IBAction func callfriendbutton(sender: AnyObject) { let phoneNumberstring ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#47iOS14 适配canOpenURL问题 - 掘金
部分升级到iOS 14的用户,在点击链接跳转的时候,*[[UIApplication sharedApplication]canOpenURL:url]返回false 经定位,是因为iOS 14新增默认浏览器 ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#48Is there something similar to iOS's canOpenURL to check URL ...
For iOS, one can check [canOpenURL] to see if a particular scheme is valid (tel://, pic2shop://). Is there anything in mobile browsers (iOS, ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#49Linking.canOpenURL cannot tell if the URL is invalid - Fantas ...
canOpenURL returns false even if Linking.openURL(url) does work. I guess this happens because at the first time the user attempts to open ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#50Linking · React Native 中文网
如果系统不知道如何处理给定的URL,则此方法会调用失败。如果你传入的URL 不是一个http 链接,则最好先通过{@code canOpenURL}方法检查一下。 对于web 链接 ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#51关于OpenSDK iOS 15系统的适配说明 - 微信开放社区
第50个之后的scheme配置会不生效,以下代码会返回NOBOOL ret = [[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:@"otherAppScheme://"]]; ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#52canOpenURL问题请教- 技术讨论 - iOSRE
if([[UIApplication sharedApplication] canOpenURL:url]) { NSLog(@“Can open VPN url”); [[UIApplication sharedApplication] openURL:url];
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#53JavaScript react-native Linking.canOpenURL Examples
JavaScript Linking.canOpenURL - 30 examples found. These are the top rated real world JavaScript examples of react-native.Linking.canOpenURL extracted from ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#54UIApplication.shared.canOpenURL implements in Qt | Qt Forum
canOpenURL (url) }. I want use this results to decide exit from Qml webview and send parameters to second application (By id package Name).
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#55ios的canopenurl是什么时候开始引入的方法 - 百度知道
ios的canopenurl是什么时候开始引入的方法. 我来答. 1个回答. #热议# 东京奥运会有哪些丑闻? 匿名用户 2017-03-07. 展开全部. 这应该在后台处理,因为前台无法处理 ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#56高晓牛 - 博客园
社交分享:-canOpenURL: failed for URL: "weixin://app/*************/" - error: "This app is not allowed to query for scheme weixin".
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#57Best explanation of the canOpenUrl: problem ever - Reddit
Does anyone have a link to information about Apple completely banning canOpenURL? Last time I heard you just had to provide a whitelist of schemes you ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#58术之多
canOpenURL : failed for URL: “weixin://app/wx 问题解决方式: 在info.plist里面添加以下 ... [iOS开发]-canOpenURL: failed for URL: "xx" - error:"This app is not ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#59ios — canOpenUrl - 此应用不允许查询方案instagram
我试图将iOS网址添加到我在iOS9中的应用程序但是我收到以下警告:-canOpenURL: failed for URL: "instragram://media?id=MEDIA_ID" - error: "This app is not allowed ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#60OStack|知识分享社区-Knowledge Sharing Community
I have the same warning, but in Facebook Docs there is an answer. This is an Xcode warning indicating the the canOpenURL: call returned ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#61ios - openURL 和canOpenURL 的区别 - 秀儿今日热榜
openURL/open 或 canOpenURL 。 谁能帮我解释一下这两个功能之间的实际区别? if #available(iOS 10.0, *) { UIApplication.shared.open(URL(string: urlStr)!, ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#62canOpenUrl-不允许该应用查询方案图 - QA Stack
-canOpenURL: failed for URL: "instragram://media?id=MEDIA_ID" - error: "This app is not allowed to query for scheme instragram".
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#63[TIMOB-14460] Android: Add Ti.Platform.canOpenURL() support
canOpenURL () to provide this functionality. On Android, I have to call Ti.Platform.openURL() and detect the returned boolean – but that ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#64iOS14 适配canOpenURL问题 - 阿里云开发者社区
部分升级到iOS 14的用户,在点击链接跳转的时候,*[[UIApplication sharedApplication]canOpenURL:url]*返回false.
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#65About -canOpenURL: and -openURL: - Programmer Sought
In general, it's mainly through the use of Apple. - canOpenURL: The API tests to see if the corresponding APP's scheme is valid.
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#66canOpenURL: failed for URL: "instagram://app"
canOpenURL : failed for URL: "instagram://app" - error: "This app is not allowed to query for scheme instagram" · -canOpenURL: failed for URL: “deep-link” — error ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#67canOpenURL:網址失敗:“instagram:// app” - 开发者知识库
[英]canOpenURL: failed for URL: “instagram://app” - error: “This app is not allowed to query for scheme instagram”.
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#68ios canOpenURL在系统宽URL方案中失败 - 開發99編程知識庫
[[UIApplcation sharedApplication] canOpenURL:@"telprompt://5555555555"]. 我們都知道,iOS 9需要我們將我們將在我們的應用程序中使用的任何URL ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#69适配ios9出现的问题:-canOpenURL: failed for URL
本来加入之前提示:-canOpenURL: failed for URL: "mqqopensdkapiV2://qzapp" - error: "This app is not allowed to query for scheme ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#70Swift 3 : canOpenURL: failed for URL:... - Auth0 Community
canOpenURL : failed for URL: “org-appextension-feature-password-management://”. error: “This app is not allowed to query for scheme
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#71iOS9友盟分享出現常見錯誤 - 壹讀
友盟分享出現以下錯誤:2016-05-06 15:16:57.158 umengShareTest[2633:1223930] -canOpenURL: failed for URL: "weixin://app/wx9df33ec7a1892500/" -
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#72swift 3/4 筆記/備忘 - mini box 迷你盒子
例如開啟FB / twitter app 參考資料: Querying URL Schemes with canOpenURL https://useyourloaf.com/blog/querying-url-schemes-with-canopenurl/
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#73Explanation of canOpenURL changes in iOS 9 | Cromulent Labs
sharedApplication().canOpenURL() in iOS 9, you must first declare the URL schemes that you want to check in your Info.plist, otherwise the call ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#74Blog - iOS 9 to Block Abuses of -canOpenURL - Michael Tsai
As you might expect from the names, “canOpenURL” returns a yes or no answer after checking if there is any apps installed on the device that ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#75-canOpenURL: failed for URL - 碼上快樂 - CODEPRJ
1、如果你的輸出信息是-canOpenURL: failed for URL: "kindle://home" - error: "This app is not allowed to query for scheme kindle".
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#76iOS呼叫系統功能與跳轉到系統設定 - IT人
if ([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:@"http://www.baidu.com/"]]) { [[UIApplication sharedApplication] ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#77ios iphone swift - UWENKU
canOpenURL : failed for URL: "instagram://app" - error: "This app is not allowed to query for scheme ... canOpenURL'用於檢查_your_應用是否可以打開該URL。
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#78Professional iOS Network Programming: Connecting the ...
After you have the scheme name, implementing the feature is relatively easy using UIApplication's canOpenURL: method. It returns YES if an application is ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#79Foundation iPhone App Development: Build An iPhone App in 5 ...
... telephoneNumber]; if ([[UIApplication sharedApplication] canopenURL: [NSURL URLWithString: callLink]]) return calllink; return nil; ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#80openURL和canOpenURL之间的区别 - 堆栈内存溢出
openURL/open 或 canOpenURL 。 谁能帮我解释一下这两个功能有什么实际区别? if #available(iOS 10.0, *) { UIApplication.shared.open(URL(string: ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#81【iOS9】特定のURLスキームのみを呼び出し可能にする ...
ここに指定がない場合やその対象となるアプリがインストールされていない場合は、.canOpenURL(url)がtrueを返しません。 「UIApplication.
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#82facebookAppURL返回false,即使安装了Facebook App
canOpenURL :facebookAppURL返回false,即使安装了Facebook App. 时间:2017-02-07 12:21:39. 标签: ios facebook url-scheme. 我想从我的iOS应用中链接一个Facebook ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#83发表回复 - 摸鱼
-canOpenURL: failed for URL: "line://" - error: "未能完成操作。(“OSStatus”錯誤-10814。)" 0. iDev • amnonma • 于 2 years ago • 140 阅读.
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#84This app is not allowed to query for scheme instragram
Im trying to add the Instagram url to my app in iOS9 however I am getting the following warning: -canOpenURL: failed for URL: ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#85PostThreadMessage 使用注意问题_weixin_30859423的博客
如: 出现-canOpenURL: failed for URL: “sinaweibohdsso://xxx” – error: “This app is not allowed to ... postMessage在网页通信中遇到的问题. 1.<iframeid="child" ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#86cannios9 openurll是什么意思 - 骄傲西网络
这里通过canOpenURL就可以通过URL检查机器是否***有程序A 通过openURL打开程序A 在CFBundleURLSchemes的分隔符不要使用_ & &比如abc_ddd
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?>
canopenurl 在 コバにゃんチャンネル Youtube 的精選貼文
canopenurl 在 大象中醫 Youtube 的最佳解答
canopenurl 在 大象中醫 Youtube 的最讚貼文