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Fibonacci and Lucas Numbers with Applications, Volume 1

By Lemma 26.1, we have p11 1 p11 1 1 tan' - tan' — – tan' ) 2. X (an"; Fon- n=1 2n Font, 1 | 1 = tan' + -tanF, Fom 12 —1 = — — tan 2 4 Fom 12 Co p11 X tan' ...

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