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Week 3 – Class 2 Solutions ICGN104 Mathematics and Its ...

(a) log11(11 3. √11)7. Solution: Since 11 3 ... √11)7 = log11(11. 4. 3 )7 = log11(11 ... Solution: We have log7 748 = 48 log7 7 = 48. (b) 10log 3.4.

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