(3.11) Now using (3.2) we get –0 cc 3 ka r3–1+3(3–1) ka rs3–2 r +q8 ko-1 rs3–1 k=53 ka rs3–1or-occo (3–1)rr-Hakk=ö.(3.12) Thus, any optimal trajectory must ...
確定! 回上一頁