So by (13.3.94:10) we get n(0)=infn2kE h"n(0)=infn2kins;21 E Znj=infj-1infn2kE Znj =infj-1n”(b(0,r2-j))=infj-1H* (b(0,r2-j)) =infj-1HO*(b(0 ...
確定! 回上一頁