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並前往https://leetcode.com/problems/implement-trie-prefix-tree/discuss/1996974/Radix-Tree-with-Comments

Radix Tree with Comments - LeetCode Discuss

struct rtnode *subtree = rtNew(head->s + i, head->last); for (int i = 0; ... if (!s[i]) return prefix; // s is partly a prefix of head->s.

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