∫x3a2+x2dx=12x2−12a2ln|a2+x2| ... ∫xax2+bx+cdx=12aln|ax2+bx+c|−ba√4ac−b2tan−12ax+b√4ac−b2 ... ∫x3exdx=(x3−3x2+6x−6)ex.
確定! 回上一頁