證明e^x微分還是一樣. Submitted by shortlin on 一, 2010-02-01 08:49. e x 求導數為. lim[dx->0][e(x+dx)-e x ]/dx. =lim[dx->0](e x e dx -e x )/dx. =lim[dx->0][e x (e dx -1)]/ ...
確定！ 回上一頁
