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並前往https://stackoverflow.com/questions/65354477/2d-array-diamond-shape-of-1s-of-size-x

2d array diamond shape of 1's of size x [duplicate]

I would harness numpy.diagflat combined with numpy.flip following way: import numpy as np arr = np.diagflat([1,1,1],2) # now we have 1s in ...

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