... Tz, JO25 J035 I.0 = 0 V.0 = -Zol.0 = 0 p.u. V.I = V2 = E. – Z11.1 = 1.0 ... V = –0.584 + 0.584 = 0 kV V. = V – V. = –0.584 – 1.168 = 1.752A180° p.u. ...
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