Tv1/ D 1, then under ̊v1 W Gv1 D Zv1=Tv1 ! H0, inductively one has that w corresponds to v1. (b) If ̊.Tv1/ ¤ 1, then ̊.Tv1/ Â Tw1 and ̊.Zv1/ Â Tw1 are open ...
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