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並前往https://books.google.com.tw/books?id=zgV5MlhlyigC&pg=PT811&lpg=PT811&dq=xslt+replace&source=bl&ots=9iCIFnAEFY&sig=ACfU3U19SG5IOhL_VH3fvFcGnDb-7_U1Xg&hl=zh-TW&sa=X&ved=2ahUKEwjCq-jRstL0AhUymeYKHWaaAa8Q6AF6BAgUEAM

XSLT 2.0 and XPath 2.0 Programmer's Reference - Google 圖書結果

So the result of replace(“banana”, “a|ana”, “#”) . is b#n#n# , whereas the result of replace(“banana”, “ana|a”, “#”) a|ana could match the second character ...

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