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j=4}^{\infty }j(j-1)(j-2)(j-3)r^{j-4}\\\end{aligned}}} - Wikimedia

... form)}}\\&0\quad 1/(1-r)\quad &&\sum _{j=0}^{\infty }r^{j}\\&1\quad 1!/(1-r)^{2}\quad &&\sum _{j=1}^{\infty }jr^{j-1}\\&2\quad 2!/(1-r)^{3}\quad &&\sum ...

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