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並前往https://leetcode-cn.com/problems/knight-probability-in-chessboard/solution/qi-shi-zai-qi-pan-shang-de-gai-lu-by-lee-2qhk/

骑士在棋盘上的概率 - 力扣

... 2}, {1, -2}, {1, 2}}; double knightProbability(int n, int k, int row, int column){ double dp[200][30][30]; memset(dp, 0, sizeof(dp)); for (int step = 0; ...

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