你即將離開本站

並前往http://ostack.cn/?qa=972318/

python - Sorting by arbitrary lambda - OStack|知识分享社区

You basically have it already: >>> mylist = [["quux", 1, "a"], ["bar", 0, "b"]] >>> mylist.sort(key=lambda x: x[1]) >>> print mylist. gives:

確定！ 回上一頁

查詢 「Python sort lambda」的人也找了：

  1. Python sort lambda
    2.
  2. Python sorted reverse
    3.
  3. Python sort dict
    4.
  4. Python sort by value
    5.
  5. Python sort key=lambda
    6.
  6. Python sort lambda multiple keys
    7.
  7. python sort key用法
    8.
  8. Python sort compare function
    9.