2Na + Cl2 → 2NaCl. ∆S = 2 × SNaCl –SCl2 – 2 × SNa. = 2 × 72 – 223 – 2 × 51. ∆S = –181/2 = – 90.5. N2 +4H2 + Cl2 → 2NH4 Cl.
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