∫ z\mathscr{C}μ(az)\mathscr{D}μ(az) dz=\tfrac{1}{4}z 2 (2\mathscr{C}μ(az)\mathscr{D}μ(az)-\mathscr{C}μ-1(az)\mathscr{D}μ+1(az)-\mathscr{C}μ+1(az)\mathscr{D}μ ...
確定! 回上一頁