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並前往https://web.njit.edu/~khera/Courses/CE443/Exmpl-Solu-handout/Review/443ReviewExmpSolu.pdf

D1E4 Example Solutions

Ws = 2.68 × 9.81×1 = 26.29 kN γd = 26.29/1.8 = 14.61 kN/m3. Vw = 0.8 m3 ... ft3 γ sat(sand). = 131.97 lb./ft3 γsat(clay) =119.65 lb./ft3 thickness ft.

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