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並前往https://www.quora.com/2-KClO3-2KCl-3O2-How-many-grams-of-potassium-chlorate-KClO3-were-reacted-if-5-30-liters-of-oxygen-O2-were-produced-at-117-C-and-0-995-ATM

2KCl + 3O2 How many grams of potassium chlorate, KClO3 ...

PV=nRT or,n= PV/RT = 0.995atm×5.30L/0.082L atm mol-1 K-1×390K = 0.1648 moles 3 moles of O2 produced from 2 moles of KClO3 Therefore, 0.1648 moles.

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