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並前往https://leetcode.com/problems/buddy-strings/discuss/141794/Java-O(1)-space-O(n)-time/161244/

Java O(1) space, O(n) time - LeetCode Discuss

B.charAt(i)) { diff++; if (a == -1) a = i; else if (b == -1) b = i; } ... B.length()) return false; // A has a duplicate character && A.equals(B) -> return ...

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