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並前往https://stackoverflow.com/questions/7486842/pow0-2-2-gives-1-in-a-hlsl-pixel-shader

pow(0, 2.2) gives 1 in a hlsl pixel shader? - Stack Overflow

Looking at the HLSL docs, pow(x, y) appears to be implemented directly as exp(y * log(x)) . Since x=0 in your question, again looking at the docs log(x) ...

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