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Show that the energy E (in eV) of a photon of wavelength λ (in ...

Energy of photon is given as. E=hcλ =6.62×10−34×3×108λ−1.99×10−25λJ 1.99×10−25λ×1.6×10−19eV 1.24λeV(μm) ∴E=1240λeV ( nm ).

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