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How to show that every Boolean ring is commutative? - Math ...

Every Boolean ring is of characteristic 2, since a+a=(a+a)2=a2+a2+a2+a2=a+a+a+a⟹a+a=0. Now, for any x,y in the ring x+y=(x+y)2=x2+xy+yx+y2=x+y+xy+yx, ...

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