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Categories for the Working Mathematician - 第 191 頁 - Google 圖書結果

First assume we have the biproduct diagram (1) with the condition (2). Then pi i2=p1(ii p1 + i2p2)i2 = 1° p1 i2 + pi i2° 1 = p, i2 + p. i2 ; subtracting, ...

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