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Archimedean Property ∀a, b ∈ R,a> 0, ∃n ∈ N, na > b. Proof ...

However, s0 − a<s0, which contradicts that s0 is the least upper bound of S. This contradiction shows that the Archimedean Property is true. Corollary 1.4.2. 1 ...

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