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Oswaal CBSE ONE for ALL Class 10 (Set of 5 Books) ...

25 cm ? 4 = πη2 Now , area of sector AOBA = хө 360 2 5 TX 12 360 x 90 So ... area of the circle = tr2 2 = TX 5 2 == 90 ° - 5 cm 2511 cm2 2 Area of minor ...

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