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Polynomials and the mod 2 Steenrod Algebra

Thus Sq°Sq'([7,4,1,1]) = Sq'Sq"(I7,3,2,1] + [7,3,1,2), and we are reduced to considering permutations of [7,3,2,1]. But Sq'Sq'(oa([7,3,2,1])) = O4([16,4,2, ...

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