... 2kT ) 3 / 2e - mc2 / 2kT c2.dc 2 VE = 2 απ ( 2.55 ) 2a2 V та Finally we consider ( again as in Eq . ( 2.20 ) ) TT 3 1 23 3 2kT c2 3kТ SOCIIcc2.c - dc So IIcc2.
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