∴ The above two equations give ni = (NCNV)½ e–Eg/2kT . ◇ n = p ⇒ NC e(EF ... 2 = Eg + 3·½m1vf. 2 m1vs = 3·m1vf. ⇒ ½m1vs. 2 = 1.5 Eg. ∴ The required kinetic ...
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