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The length of a rod is 2.5 cm and diameter is 2.5 mm. The ...

l = 2.5 cm, diameter = 2.5 mm =2.5xx10^(-1)cm=0.25cm Radius, r=0.125cm "Volume of the rod "=pir^(2)l=3.1428xx0.125xx0.125xx2.5 Here 2.5 has ...

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