... depth of H2CO as follows TJJ2~s = Aj12~s (vL~v)jj2~oNjj2c~ _____ TH2CO AH2CO (VL\v)112cs N112~0 TH2CS - V112cs I Sij 1 2112CS N~ T112c0 VH2CO Sz~ 2112C0 ...
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