(x-h)^2 / A +(y-k)^2 /B = 1 , A.B可正可負, 證明:斜率m的兩條切線: y-k=m(x-h)+(Am^2+B)^(1/2) y-k=m(x-h)-(Am^2+B)^(1/2) @ @ wang620628.
確定! 回上一頁