雖然這篇UIUserInterfaceIdiom鄉民發文沒有被收入到精華區:在UIUserInterfaceIdiom這個話題中,我們另外找到其它相關的精選爆讚文章
[爆卦]UIUserInterfaceIdiom是什麼?優點缺點精華區懶人包
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#1UIUserInterfaceIdiom | Apple Developer Documentation
Constants that indicate the interface type for the device or an object that has a trait environment, such as a view and view controller. Availability.
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#2Detect current device with UI_USER_INTERFACE_IDIOM() in ...
When working with Swift, you can use the enum UIUserInterfaceIdiom , defined as: enum UIUserInterfaceIdiom : Int { case unspecified case phone // iPhone and ...
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#3在Swift中使用UIUserInterfaceIdiom检测当前设备 - 码农家园
Detect current device with UIUserInterfaceIdiom in Swift要使用iOS / Swift检测当前设备,我们可以使用UserInterfaceIdiom。 它是一个快速枚举, ...
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#4UIUserInterfaceIdiom Enum (UIKit) | Microsoft Docs
Unavailable(ObjCRuntime.PlatformName.WatchOS, ObjCRuntime.PlatformArchitecture.All, null)] public enum UIUserInterfaceIdiom type UIUserInterfaceIdiom =.
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#5Detect current device with UIUserInterfaceIdiom in Swift
Detect current device with UIUserInterfaceIdiom in Swift ... To detect current device with iOS/Swift we can use UserInterfaceIdiom. It is an enum ...
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#6Java UIUserInterfaceIdiom類代碼示例- 純淨天空
本文整理匯總了Java中org.robovm.apple.uikit.UIUserInterfaceIdiom類的典型用法代碼示例。如果您正苦於以下問題:Java UIUserInterfaceIdiom類的具體用法?
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#7Swift UIUserInterfaceIdiom错误 - IT工具网
我只在iPhone 5/6/6 Plus/iPad mini/iPad的横向视图中使用,现在我想在我的应用程序中集成uiuserinterfaceidiom,以便在横向视图中使用这些设备。
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#8【IPHONE】UIUserInterfaceIdiom電話也適用於iPod touch嗎?
【IPHONE】UIUserInterfaceIdiom電話也適用於iPod touch嗎? 2020-11-17 IPHONE. 很抱歉這個愚蠢的問題,但我在任何地方都找不到很好的答案。
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#9Use of undeclared type UIDevice and UIUserInterfaceIdiom
When adding Iterable using SPM, I get the following erros when trying to build: Use of undeclared type 'UIUserInterfaceIdiom' Use of ...
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#10apple.uikit.UIDevice.userInterfaceIdiom java code examples
if (UIDevice.currentDevice().userInterfaceIdiom() == UIUserInterfaceIdiom.Pad) {... if (UIDevice.currentDevice().
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#11UIUserInterfaceIdiom (cmioslayer 3.4.0 API) - CrossMobile
public final class UIUserInterfaceIdiom extends Object. UIUserInterfaceIdiom class defines the type of user interface that should be designed for the device ...
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#12iOS) UIDevice 사용해서 Autolayout 기기대응하기 - hyun9iOS
userInterfaceIdiom == UIUserInterfaceIdiom.phone && (UIScreen.main.bounds.size.height == 568 && UIScreen.main.bounds.size.width == 320) ...
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#13在Swift中使用UI_USER_INTERFACE_IDIOM ... - QA Stack
enum UIUserInterfaceIdiom : Int { case unspecified case phone // iPhone and iPod touch style UI case pad // iPad style UI (also includes macOS Catalyst) }.
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#14Detect current device with UI_USER_INTERFACE_IDIOM() in ...
When working with Swift, you can use the enum UIUserInterfaceIdiom, defined as: enum UIUserInterfaceIdiom : Int { case unspecified case phone // iPhone and ...
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#15iPhone iPad 等设备区分[UI适配] - 简书
UI_USER_INTERFACE_IDIOM(); UIUserInterfaceIdiom. UI_USER_INTERFACE_IDIOM() 是一个内联函数,它是用来获取设备的UI类型,比如iPhone 的UI类型,该 ...
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#16Question : if (device == iPad), if (device == iPhone) - TitanWolf
You can also check the UIUSerInterfaceIdiom and choose the device you want to UIUserInterfaceIdiom.Pad or UIUserInterfaceIdiom.Phone or UIUserInterfaceIdiom ...
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#17Improve iPad Sidebar Navigation on the iPhone With SwiftUI
To do that, we should use the UIUserInterfaceIdiom enum. It can answer the question of what kind of device the app is running, starting with ...
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#18How to test code that depends on UIUserInterfaceIdiom (ios)
I have some Objective-C [i-os] code that I would like to run unit tests over using XCode. It accesses different metadata depending on the type of device, ...
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#19DevicePpi on CocoaPods.org
... provides a "best guess" PPI based on heuristics ( UIUserInterfaceIdiom and UIScreen values) and an error code which you can treat as a non-fatal error.
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#20Appendix - Complete Examples - LiveCode Downloads
wrap objc UIDevice -(UIUserInterfaceIdiom)userInterfaceIdiom return result end handler handler UIDeviceGetIdentifierForVendor(in pDevice as UIDevice) \.
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#21Swift UIUserInterfaceIdiom ошибка - CodeRoad
я использую вид только в ландшафте для iphone 5/6/6 Plus / iPad Mini/iPad, и теперь я хотел бы интегрировать UIUserInterfaceIdiom в свое приложение для ...
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#22API to determine whether running on iPhone or iPad [duplicate]
UIUserInterfaceIdiom. The type of interface that should be used on the current device. typedef enum { UIUserInterfaceIdiomPhone, UIUserInterfaceIdiomPad, } ...
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#23Swift UIUserInterfaceIdiom错误- 程序调试信息网
我只在iPhone 5/6/6 Plus/iPad mini/iPad的横向视图中使用,现在我想在我的应用程序中集成uiuserinterfaceidiom,以便在横向视图中使用这些设备。
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#24App crash on AttachmentButton - General Questions
0 { dismissKeyboard() } if ( UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.pad ){ if let currentPopoverpresentioncontroller ...
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#25Device / Form Factor Detection - Craft
From iOS 14 / MacOS 11 you can utilize the UIUserInterfaceIdiom.mac to detect this - however if you target earlier OS-es this is not available.
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#26使用Swift中的UI_USER_INTERFACE_IDIOM()检测当前设备
使用Swift时,可以使用 enum UIUserInterfaceIdiom ,定义如下: enum UIUserInterfaceIdiom : Int { case unspecified case phone // iPhone and iPod touch style UI ...
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#27取得裝置資訊· Swift hack
取得裝置資訊. override func viewDidLoad() { // Init super.viewDidLoad() // 有些我直接假設你看得懂 // switch Type: enum UIUserInterfaceIdiom switch ...
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#28Here is how to programmatically identify if user is on iPhone or ...
userInterfaceIdiom == UIUserInterfaceIdiom.pad) {. print ( "It's iPad" ). // Your code here. } else if (UIScreen.main.traitCollection.
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#29iPad和iPhone的設定判斷-技術 - 拾貝文庫網
為了開發同時相容 iPhone 和iPad 的應用,可以通過iOS 提供的 UIDevice 類,該物件的 userInterfaceIdiom 屬性返回一個UIUserInterfaceIdiom 列舉值,該列舉值包含如下兩 ...
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#30iOS获取设备信息- 云+社区 - 腾讯云
userInterfaceIdiom); // 详见UIUserInterfaceIdiom } </pre> 打印结果: 2015-01-29 11:35:23.294 TestProject[261:60b] 设备名称- iPhone ...
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#31iphone到ipad的转换 - 955Yes
... iPhone and iPod touch style UI UIUserInterfaceIdiomPad, // iPad style UI } UIUserInterfaceIdiom; #define UI_USER_INTERFACE_IDIOM() ...
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#32Checking version and device when restoring state - Use Your ...
... integerValue]; UIUserInterfaceIdiom currentInterfaceIdiom = currentDevice.userInterfaceIdiom; if (restorationInterfaceIdiom !=
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#33ios - 应用程序在sendEvent 方法上崩溃- Cache One
addChildViewController(loginViewController) return } if idiom == UIUserInterfaceIdiom.Phone{ currentState = AppState.PHONE leftNavigationController?
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#34SwiftでiPhoneとiPadを判別する - Qiita
enum UIUserInterfaceIdiom : Int { case Unspecified case Phone // iPhone and iPod case Pad // iPad }. このような定義があるので、判別は下記の ...
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#35Ben Dodson on Twitter: "Interesting that iOS 9.3 has a new ...
Interesting that iOS 9.3 has a new UIUserInterfaceIdiom for CarPlay… 9:37 AM · Mar 23, 2016·Tweetbot for Mac.
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#36Определить текущее устройство с помощью ... - overcoder
При работе с Swift вы можете использовать enum UIUserInterfaceIdiom, определяемый как: enum... Вопрос по теме: swift, ios, objective-c, iphone, ipad.
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#37设备类型判断- iOS - CSDN博客
其中UIUserInterfaceIdiom 是对应不同设备的参数,根据不同的条件语句进行相应的功能实现即 ... typedef NS_ENUM(NSInteger, UIUserInterfaceIdiom) {.
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#38ตรวจจับอุปกรณ์ปัจจุบันด้วย UI_USER_INTERFACE_IDIOM () ใน ...
enum UIUserInterfaceIdiom : Int { case unspecified case phone // iPhone and iPod touch style UI case pad // iPad style UI (also includes macOS Catalyst) }.
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#39UIDevice 文件 - 開發者的工作室
UIDeviceOrientation;//旋轉 UIDeviceBatteryState;//電池 UIUserInterfaceIdiom;//裝置(ipad ,iphone)版本判定. 你可以抓出一些資訊,像是.
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#40iOS SDK具体解释之UIDevice(系统版本号,设备型号...)
enum UIUserInterfaceIdiom : Int { case Unspecified case Phone //iPhone 和iTouch case Pad //Ipad }. 1. 2. 3. 4. 5. let deviceType = UIDevice.
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#41by Minkyu Hwang on SnipSave | Web-based code snippet ...
static inline UIUserInterfaceIdiom UI_USER_INTERFACE_IDIOM() API_DEPRECATED("Use -[UIDevice userInterfaceIdiom] directly.", ios(2.0, 13.0), tvos(9.0, ...
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#42iOS 手機||平板判斷- IT閱讀
iOS 手機||平板判斷. 2019-01-21 254. typedef NS_ENUM(NSInteger, UIUserInterfaceIdiom) {. UIUserInterfaceIdiomUnspecified = -1,.
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#43ios : SwiftのUI_USER_INTERFACE_IDIOM()で現在の ...
public enum UIUserInterfaceIdiom:Int {case Unspecified @available(iOS 3.2、*)case Phone //iPhoneおよびiPodtouchスタイルのUI ...
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#44sendEvent方法导致应用程序崩溃- ios - 摸鱼
addChildViewController(loginViewController) return } if idiom == UIUserInterfaceIdiom.Phone{ currentState = AppState.PHONE leftNavigationController?
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#45【iOS - UIKit】居然是村长
... UIUserInterfaceIdiom) { UIUserInterfaceIdiomUnspecified = -1, UIUserInterfaceIdiomPhone, // iPhone and iPod touch style UI UIUserInterfaceIdiomPad, ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#46React Native : iOS - Use of undeclared identifier - GAME DEV ...
... so i'm just comment out in file "RCTPlatform.m" under function "static NSString *interfaceIdiom(UIUserInterfaceIdiom idiom)" like this.
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#47[Swift] iOS 디바이스별 화면에 맞는 코딩하기 - 블로그
userInterfaceIdiom == UIUserInterfaceIdiom.phone {. return true. } return false. } public var isiPad: Bool {. if UIDevice.current.
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#48[ios/code snippet] Phone 인지 Pad 인지 검사하기 - 돼지왕 놀이터
UIUserInterfaceIdiom userInterfcae = [UIDevice currentDevice].userInterfaceIdiom;. if ( userInterfcae == UIUserInterfaceIdiomPad ) {.
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#49How to differentiate iPhone and iPad in universal application?
UserInterfaceIdiom == UIUserInterfaceIdiom.Phone) { Console.WriteLine("Phone"); } else if (UIDevice.CurrentDevice.UserInterfaceIdiom == UIUserInterfaceIdiom ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#50iPhoneかiPadかを判別して処理を分岐させる - おすしたべたい
UI_USER_INTERFACE_IDIOM() を調べてみると UIDevice のヘッダにインライン関数が定義されていました。 static inline UIUserInterfaceIdiom ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#51Chris Parker - Huihoo
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {. // Create a popover controller here. UIPopoverController *popoverController ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#52iOS Confusion about printing out a certain enum - MacRumors ...
userInterfaceIdiom is UIUserInterfaceIdiom". I'm confused why it isn't printing "phone", which it actually is set to. If I checked if "self.
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#53通過iPhone裝置的identifier精確判斷裝置型號和是否是全屏裝置
... public var isPhone: Bool { return userInterfaceIdiom == UIUserInterfaceIdiom.phone } public var iPhoneGeneration: iPhoneDevice?
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#54设备类型判断- iOS - 代码先锋网
其中UIUserInterfaceIdiom 是对应不同设备的参数,根据不同的条件语句进行相应的功能实现即可;. typedef NS_ENUM(NSInteger, UIUserInterfaceIdiom) {.
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#55在Swift中使用UI_USER_INTERFACE_IDIOM ... - 编程字典
使用Swift时,您可以使用 enum UIUserInterfaceIdiom ,定义为: enum UIUserInterfaceIdiom : Int { case unspecified case phone // iPhone and iPod touch style UI ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#56端末の識別ができない(UIUserInterfaceIdiom) - Teratail
userInterfaceIdiom のリファレンスに、. The style of interface to use on the current device. と書かれているので、端末の種類ではなく、 ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#57objective c - iOS检测用户是否在iPad上
//MARK: - Device Check let iPad = UIUserInterfaceIdiom.Pad let iPhone = UIUserInterfaceIdiom.Phone @available(iOS 9.0, *) /* AppleTV check ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#58iOS detect if user is on an iPad - ICT-英国电信国际电话会议
//MARK: - Device Check let iPad = UIUserInterfaceIdiom.Pad let iPhone = UIUserInterfaceIdiom.Phone @available(iOS 9.0, *) /* AppleTV check is iOS9+ */ let ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#59Choosing a User Interface Idiom for Your Mac App - velog
UIUserInterfaceIdiom.pad idiom에서 앱을 실행합니다. 아이패드 앱을 맥으로 빠르게 가져오기 위해 이 옵션을 선택할 수 있습니다. Optimize Interface ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#60MobiVM/robovm - Gitter
getUserInterfaceIdiom() == UIUserInterfaceIdiom.Phone) { //iPhone rootViewController.presentViewController( share, true, null); } else { //iPad ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#61判断是否为iPad设备语句是?__牛客网
typedef NS_ENUM(NSInteger, UIUserInterfaceIdiom) { UIUserInterfaceIdiomUnspecified = -1, #if __IPHONE_3_2 <= __IPHONE_OS_VERSION_MAX_ALLOWED
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#62objective-c — if (device == iPad), if (device == iPhone) - ti ...
Você também pode verificar o UIUSerInterfaceIdiom e escolher o dispositivo que deseja UIUserInterfaceIdiom.Pad ou UIUserInterfaceIdiom.
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#63iphone-sdk中的宏定义(一) - 月光的尽头- 博客园
(UIUserInterfaceIdiom)userInterfaceIdiom是一个枚举,包括:UIUserInterfaceIdiomPhone,UIUserInterfaceIdiomPad.
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#64Swift에서 UI_USER_INTERFACE_IDIOM ()으로 현재 장치 감지
나는 얻을 Use of unresolved identifier 스위프트에 컴파일 할 때 오류가 발생했습니다. Swift로 작업 할 때 enum UIUserInterfaceIdiom 다음과 같이 ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#65Detect current device with UI USER INTERFACE IDIOM() in Swift
Podczas pracy z Swift, możesz użyć enum UIUserInterfaceIdiom , zdefiniowany jako: enum UIUserInterfaceIdiom : Int { case unspecified case phone // iPhone ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#66AppleTraitCollection - UBogun/Xojo-iosLib Wiki
Constructor (UserInterfaceIdiom as UIUserInterfaceIdiom): Returns a new trait collection containing only a specified interface idiom.
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#67IDAObjcTypes - githubmemory
Example: typedef NS_ENUM(NSInteger, UIUserInterfaceIdiom) { UIUserInterfaceIdiomUnspecified = -1, UIUserInterfaceIdiomPhone = 0, UIUserInterfaceIdiomPad = 1 ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#68Simulating side-by-side Xcode Previews | Marcos Griselli
... UIUserInterfaceSizeClass let verticalSizeClass: UIUserInterfaceSizeClass let userInterfaceIdiom: UIUserInterfaceIdiom let orientation: ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#69Swift Code in App Delegate to Load Storyboard Causes Crash
userInterfaceIdiom if deviceIdiom == UIUserInterfaceIdiom.Phone { strDevice = "iPhone" } else if deviceIdiom == UIUserInterfaceIdiom.
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#70Ошибка Swift UIUserInterfaceIdiom - Answer-ID
Вы должны сделать это вот так: if UIDevice.currentDevice().userInterfaceIdiom == UIUserInterfaceIdiom.Phone { //..... } вы также можете создать вычисляемое ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#71Hello Swift! - Mastering iOS
Before iOS 8, you would use UIInterfaceOrientation and UIUserInterfaceIdiom to differentiate between portrait and landscape and iPhone and ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#72根据屏幕分辨率判断当前手机型号(swift4.1) - 知乎专栏
userInterfaceIdiom == UIUserInterfaceIdiom.phone) { //判断是否为竖屏 if (iOSDeviceScreenSize.height > iOSDeviceScreenSize.width){
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#73if (dispositivo == iPad), if (dispositivo == iPhone) - it-swarm-es ...
También puede verificar UIUSerInterfaceIdiom y elegir el dispositivo que desea UIUserInterfaceIdiom.Pad o UIUserInterfaceIdiom.Phone o UIUserInterfaceIdiom.
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#74Erkennen Sie das aktuelle Gerät mit ... - QA Stack
enum UIUserInterfaceIdiom : Int { case unspecified case phone // iPhone and iPod touch style UI case pad // iPad style UI (also includes macOS Catalyst) }.
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#75使用Swift中的UI_USER_INTERFACE_IDIOM()检测当前设备
使用Swift时,您可以使用 enum UIUserInterfaceIdiom ,定义为: enum UIUserInterfaceIdiom : Int { case unspecified case phone // iPhone and iPod touch style UI ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#76[ SWIFT ] - FUNC - 判斷裝置與取得目前裝置方向& SIZE
userInterfaceIdiom == UIUserInterfaceIdiom.Pad). {NSLog("裝置為iPad")}. if( self.traitCollection.userInterfaceIdiom == UIUserInterfaceIdiom.
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#77iOS get device information - Krybot
userInterfaceIdiom);//See UIUserInterfaceIdiom for details }. Print result: 2015-01-29 11:35:23.294 TestProject[261:60b] Device name-iPhone 2015-01-29 ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#78分享功能使用的UIPopoverController在iOS9 過期
userInterfaceIdiom == UIUserInterfaceIdiom.Phone) { 2 presentViewController(vc, animated: true, completion: nil) 3 } else if (popover == nil ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#79用于确定是在iPhone还是iPad上运行的API - 探索字符串
UIUserInterfaceIdiom. The type of interface that should be used on the current device. typedef enum { UIUserInterfaceIdiomPhone, UIUserInterfaceIdiomPad, } ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#80How does one get UI_USER_INTERFACE_IDIOM() to work ...
При работе с Swift вы можете использовать enum UIUserInterfaceIdiom, определяемый как: enum Вопрос по теме: swift, ios, objective-c, iphone, ipad. String Not ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#81UIUserInterfaceIdiom (ios)에 의존하는 코드를 테스트하는 방법
ios - UIUserInterfaceIdiom (ios)에 의존하는 코드를 테스트하는 방법. 기사 출처 ios xcode unit-testing octest. XCode를 사용하여 단위 테스트를 실행하려는 ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#82Comment tester le code qui dépend de UIUserInterfaceIdiom ...
Comment tester le code qui dépend de UIUserInterfaceIdiom (iOS). J'ai du code Objective-C [i-os] sur lequel j'aimerais exécuter des tests unitaires en ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#83在Swift中使用UI_USER_INTERFACE_IDIOM()檢測當前設備
使用Swift時,您可以使用 enum UIUserInterfaceIdiom , 定義為: enum UIUserInterfaceIdiom : Int { case unspecified case phone // iPhone and iPod touch style ...
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?> -
//=++$i?>//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['title'])?>
#84Ios 枚举数的重新定义-Obj-C
我想您可以删除此代码,UIUserInterfaceIdiom已经在UIDevice.h我想您可以删除此代码,UIUserInterfaceIdiom已经在UIDevice.h中定义. 我在一个旧的iOS应用程序(4.3!
//="/exit/".urlencode($keyword)."/".base64url_encode($si['_source']['url'])."/".$_pttarticleid?>//=htmlentities($si['_source']['domain'])?>
uiuserinterfaceidiom 在 コバにゃんチャンネル Youtube 的精選貼文
uiuserinterfaceidiom 在 大象中醫 Youtube 的最佳貼文
uiuserinterfaceidiom 在 大象中醫 Youtube 的精選貼文